What is the solution for y^'=(t+1)/(ty+t) ?

The solution for y^'=(t+1)/(ty+t) is y=-1+sqrt(2(t+ln(t)+c_{1))+1},y=-sqrt(2(t+ln(t)+c_{1))+1}-1

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y^'=(t+1)/(ty+t)

y^{^{'}} = \frac{t + 1}{t y + t}

y = - 1 + 2 (t + ln (t) + c_{1}) + 1, y = - 2 (t + ln (t) + c_{1}) + 1 - 1

Solution steps

y^{'} (t) = \frac{t + 1}{t y + t}

Solve separable ODE:

y = - 1 + 2 (t + ln (t) + c_{1}) + 1, y = - 2 (t + ln (t) + c_{1}) + 1 - 1

y = - 1 + 2 (t + ln (t) + c_{1}) + 1, y = - 2 (t + ln (t) + c_{1}) + 1 - 1

What is the solution for y^'=(t+1)/(ty+t) ?
The solution for y^'=(t+1)/(ty+t) is y=-1+sqrt(2(t+ln(t)+c_{1))+1},y=-sqrt(2(t+ln(t)+c_{1))+1}-1