What is the solution for cos(2y)dy=dx ?

The solution for cos(2y)dy=dx is y=(arcsin(2x+c_{1}))/2+pin,y= pi/2+(arcsin(-2x-c_{1}))/2+pin

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cos(2y)dy=dx

cos (2 y) d y = d x

y = \frac{arcsin ( 2 x + c _{1} )}{2} + πn, y = \frac{π}{2} + \frac{arcsin ( - 2 x - c _{1} )}{2} + πn

Solution steps

cos (2 y) d y = d x

Solve separable ODE:

y = \frac{arcsin ( 2 x + c _{1} )}{2} + πn, y = \frac{π}{2} + \frac{arcsin ( - 2 x - c _{1} )}{2} + πn

y = \frac{arcsin ( 2 x + c _{1} )}{2} + πn, y = \frac{π}{2} + \frac{arcsin ( - 2 x - c _{1} )}{2} + πn

What is the solution for cos(2y)dy=dx ?
The solution for cos(2y)dy=dx is y=(arcsin(2x+c_{1}))/2+pin,y= pi/2+(arcsin(-2x-c_{1}))/2+pin