(dy)/(dx)=(x^2)/(x^2(3y^2+1)),y(1)=4

解答

\frac{d y}{d x} = \frac{x ^{2}}{x ^{2} ( 3 y ^{2} + 1 )}, y (1) = 4

\frac{1}{49}

十进制

0.02040 \dots

求解步骤

\frac{x ^{2}}{x ^{2} ( 3 y ^{2} + 1 )} = \frac{x ^{2}}{x ^{2} ( 3 y ^{2} + 1 )}

常数函数结果为常数

y (1) = 4

= \frac{x ^{2}}{x ^{2} ( 3 \cdot 4 ^{2} + 1 )}

乘开

\frac{x ^{2}}{x ^{2} ( 3 \cdot 4 ^{2} + 1 )} : \frac{1}{49}

= \frac{1}{49}