What is the solution for dv=sin(x)dx ?

The solution for dv=sin(x)dx is x=arccos(-v-c_{1})+2pin,x=-arccos(-v-c_{1})+2pin

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dv=sin(x)dx

d v = sin (x) d x

x = arccos (- v - c_{1}) + 2 πn, x = - arccos (- v - c_{1}) + 2 πn

Solution steps

d v = sin (x) d x

Solve separable ODE:

x = arccos (- v - c_{1}) + 2 πn, x = - arccos (- v - c_{1}) + 2 πn

x = arccos (- v - c_{1}) + 2 πn, x = - arccos (- v - c_{1}) + 2 πn

What is the solution for dv=sin(x)dx ?
The solution for dv=sin(x)dx is x=arccos(-v-c_{1})+2pin,x=-arccos(-v-c_{1})+2pin