What is the solution for (x^2-3)(dy)/(dx)=x(y^2+16),y(2)=4 ?

The solution for (x^2-3)(dy)/(dx)=x(y^2+16),y(2)=4 is y=4tan(2ln(x^2-3)+pi/4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(x^2-3)(dy)/(dx)=x(y^2+16),y(2)=4

(x^{2} - 3) \frac{d y}{d x} = x (y^{2} + 16), y (2) = 4

y = 4 tan (2 ln (x^{2} - 3) + \frac{π}{4})

Solution steps

(x^{2} - 3) \frac{d y}{d x} = x (y^{2} + 16)

Solve separable ODE:

y = 4 tan (2 ln (x^{2} - 3) + \frac{π}{4})

y = 4 tan (2 ln (x^{2} - 3) + \frac{π}{4})

What is the solution for (x^2-3)(dy)/(dx)=x(y^2+16),y(2)=4 ?
The solution for (x^2-3)(dy)/(dx)=x(y^2+16),y(2)=4 is y=4tan(2ln(x^2-3)+pi/4)