What is the solution for y^'=(xy+x+y+1)/(xy+2x-y-2) ?

The solution for y^'=(xy+x+y+1)/(xy+2x-y-2) is y=\W(((-1+x)^2)/(e^{-c_{1)-x-1}})-1

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y^'=(xy+x+y+1)/(xy+2x-y-2)

y^{^{'}} = \frac{x y + x + y + 1}{x y + 2 x - y - 2}

y = W (\frac{( - 1 + x ) ^{2}}{e ^{- c_{1} - x - 1}}) - 1

Solution steps

y^{'} (x) = \frac{x y + x + y + 1}{x y + 2 x - y - 2}

Solve separable ODE:

y = W (\frac{( - 1 + x ) ^{2}}{e ^{- c_{1} - x - 1}}) - 1

y = W (\frac{( - 1 + x ) ^{2}}{e ^{- c_{1} - x - 1}}) - 1

What is the solution for y^'=(xy+x+y+1)/(xy+2x-y-2) ?
The solution for y^'=(xy+x+y+1)/(xy+2x-y-2) is y=\W(((-1+x)^2)/(e^{-c_{1)-x-1}})-1