What is the solution for y^'=12xy-2x,y(0)=17 ?

The solution for y^'=12xy-2x,y(0)=17 is y=(101e^{6x^2})/6+1/6

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y^'=12xy-2x,y(0)=17

y^{^{'}} = 12 x y - 2 x, y (0) = 17

y = \frac{101 e ^{6 x^{2}}}{6} + \frac{1}{6}

Solution steps

y^{'} (x) = 12 x y - 2 x

Solve separable ODE:

y = \frac{101 e ^{6 x^{2}}}{6} + \frac{1}{6}

y = \frac{101 e ^{6 x^{2}}}{6} + \frac{1}{6}

What is the solution for y^'=12xy-2x,y(0)=17 ?
The solution for y^'=12xy-2x,y(0)=17 is y=(101e^{6x^2})/6+1/6