What is the solution for (x^2)/(y^2-3)(dy)/(dx)= 1/(2y),y(1)=2 ?

The solution for (x^2)/(y^2-3)(dy)/(dx)= 1/(2y),y(1)=2 is y=sqrt(e^{-1/x+1)+3}

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(x^2)/(y^2-3)(dy)/(dx)= 1/(2y),y(1)=2

\frac{x ^{2}}{y ^{2} - 3} \frac{d y}{d x} = \frac{1}{2 y}, y (1) = 2

y = e^{- \frac{1}{x} + 1} + 3

Solution steps

\frac{x ^{2}}{y ^{2} - 3} \frac{d y}{d x} = \frac{1}{2 y}

Solve separable ODE:

y = e^{- \frac{1}{x} + 1} + 3

y = e^{- \frac{1}{x} + 1} + 3

What is the solution for (x^2)/(y^2-3)(dy)/(dx)= 1/(2y),y(1)=2 ?
The solution for (x^2)/(y^2-3)(dy)/(dx)= 1/(2y),y(1)=2 is y=sqrt(e^{-1/x+1)+3}