What is the solution for (x^2+e^x)dx+ydy=0 ?

The solution for (x^2+e^x)dx+ydy=0 is y=sqrt((-2x^3-6e^x+c_{1))/3},y=-sqrt((-2x^3-6e^x+c_{1))/3}

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(x^2+e^x)dx+ydy=0

(x^{2} + e^{x}) d x + y d y = 0

y = \frac{- 2 x ^{3} - 6 e ^{x} + c _{1}}{3}, y = - \frac{- 2 x ^{3} - 6 e ^{x} + c _{1}}{3}

Solution steps

(x^{2} + e^{x}) d x + y d y = 0

Solve separable ODE:

y = \frac{- 2 x ^{3} - 6 e ^{x} + c _{1}}{3}, y = - \frac{- 2 x ^{3} - 6 e ^{x} + c _{1}}{3}

y = \frac{- 2 x ^{3} - 6 e ^{x} + c _{1}}{3}, y = - \frac{- 2 x ^{3} - 6 e ^{x} + c _{1}}{3}

What is the solution for (x^2+e^x)dx+ydy=0 ?
The solution for (x^2+e^x)dx+ydy=0 is y=sqrt((-2x^3-6e^x+c_{1))/3},y=-sqrt((-2x^3-6e^x+c_{1))/3}