sum from n=0 to infinity of (1+7n)^{1/2}

Lösung

n = 0 \sum \infty (1 + 7 n)^{\frac{1}{2}}

divergiert

Schritte zur Lösung

n = 0 \sum \infty (1 + 7 n)^{\frac{1}{2}}

Seriendivergenztest anwenden:

divergiert

= divergiert

n = 1 \sum \infty \frac{1}{( n ) ^{2}}

n = 0 \sum \infty \frac{9}{5 ^{n}}

n = 1 \sum \infty \frac{2 n}{1 + n ^{2}}

n = 1 \sum \infty \frac{( 2 ) ^{n}}{n}

k = 4 \sum \infty \frac{6}{k} - \frac{6}{k + 1}