Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Telescoping Series Test:
Simplify

Popular Examples

sum from n=1 to infinity of 1/(5^{3n)}sum from n=0 to infinity of ((-1^n))/nsum from n=0 to infinity of e^{1/2}sum from n=1 to infinity of 1/(ln(5^n))sum from n=0 to infinity of (1/(1.02))^n

Frequently Asked Questions (FAQ)

  • What is the sum from k=0 to infinity of 2/(k^2+k) ?

    The sum from k=0 to infinity of 2/(k^2+k) is 2