Solution

Solution

Solution steps
Apply Series Ratio Test:converges

Popular Examples

sum from n=2 to infinity of sin(n)sum from n=1 to infinity of 10^{2n}sum from n=-21 to infinity of-126sum from n=2 to infinity of n-1sum from n=1 to infinity of 5*0.02^{n-1}

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of ne^{(-n^2)} ?

    The sum from n=1 to infinity of ne^{(-n^2)} is converges