Solution

Solution

Solution steps
Apply Series Divergence Test:diverges

Popular Examples

sum from n=1 to infinity of 6(1/5)^{n-1}sum from n=1 to infinity of 6ne^{-n^2}sum from k=1 to infinity of 8/(k^7+9)sum from n=1 to infinity of ne^{-n/9}sum from n=1 to infinity of 1/(n^3+3)

Frequently Asked Questions (FAQ)

  • What is the sum from k=0 to infinity of k/(4k+1) ?

    The sum from k=0 to infinity of k/(4k+1) is diverges