Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Comparison Test:diverges

Popular Examples

sum from k=0 to infinity of k/(4k+1)sum from n=1 to infinity of 6(1/5)^{n-1}sum from n=1 to infinity of 6ne^{-n^2}sum from k=1 to infinity of 8/(k^7+9)sum from n=1 to infinity of ne^{-n/9}

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of 2/(3n-1) ?

    The sum from n=1 to infinity of 2/(3n-1) is diverges