Solution

Solution

Solution steps
Apply the constant multiplication rule:
by the Raabe's test

Popular Examples

sum from n=1 to infinity of 1+sin^2(n)sum from n=5 to infinity of (2/11)^nsum from n=1 to infinity of 4(-1/2)^nsum from k=1 to infinity of (k-5)/(k+2)sum from n=0 to infinity of 1/(n*(n+1))

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of 5(3/2)^n ?

    The sum from n=1 to infinity of 5(3/2)^n is diverges