Solution

Solution

Solution steps
Factor
Apply the constant multiplication rule:
Apply Series Comparison Test:diverges

Popular Examples

sum from n=1 to infinity of e^n+e^{-n}sum from n=1 to infinity of n/(7n^2+1)sum from n=0 to infinity of 5/(4^n-3^n)sum from n=0 to infinity of 7sum from n=1 to infinity}(e^{3n of)/(n!)

Frequently Asked Questions (FAQ)

  • What is the sum from n=0 to infinity of 1/(5-n) ?

    The sum from n=0 to infinity of 1/(5-n) is diverges