Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Ratio Test:converges

Popular Examples

sum from n=3 to infinity of 7/(3ln(n))sum from n=1 to infinity of 1/(n(n^2+1))sum from n=0 to infinity of 3(1/3)^nsum from n=0 to infinity of n^{-1/2}sum from x=1 to infinity of (ln(x))/x

Frequently Asked Questions (FAQ)

  • What is the sum from k=1 to infinity of 6(1/5)^{k-1} ?

    The sum from k=1 to infinity of 6(1/5)^{k-1} is converges