Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Ratio Test:converges

Popular Examples

sum from n=1 to infinity of 4/(n^2+n^3)sum from k=0 to infinity of (0.9)^ksum from n=1 to infinity of 1/(2(n+1))sum from n=0 to infinity of 0.999^nsum from n=1 to infinity of n/(1+n)

Frequently Asked Questions (FAQ)

  • What is the sum from i=1 to infinity of 4(2/5)^{i-1} ?

    The sum from i=1 to infinity of 4(2/5)^{i-1} is converges