Solution

Solution

Solution steps
Apply Series Ratio Test:converges

Popular Examples

sum from n=1 to infinity of (-0.005)^nsum from n=1 to infinity of 2/(nln(9n))sum from n=1 to infinity of (n!)/(116^n)sum from n=1 to infinity of 1/(5^n-2)sum from n=1 to infinity of 5(1/2)^{n+1}

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of ne^{-16n} ?

    The sum from n=1 to infinity of ne^{-16n} is converges