Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Comparison Test:diverges

Popular Examples

sum from n=1 to infinity of (5/n)^nsum from k=1 to infinity of 4/k+8^{-k}sum from n=0 to infinity}(e^{1/n of)/nsum from k=4 to infinity of 1/(k^2-k)sum from n=1 to infinity of (e^n)/(4^n)

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of (3n)/(n^2+3) ?

    The sum from n=1 to infinity of (3n)/(n^2+3) is diverges