Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Divergence Test:diverges

Popular Examples

sum from n=0 to infinity of 20sum from n=0 to infinity of (2-4/n)^5sum from n=6 to infinity of 1/n-1/(n+3)sum from n=0 to infinity of 1/(8n-1)sum from n=1 to infinity of (sin(200))^n

Frequently Asked Questions (FAQ)

  • What is the sum from n=0 to infinity of 4n ?

    The sum from n=0 to infinity of 4n is diverges