Solution
Solution
Solution steps
Apply the constant multiplication rule:
Apply Series Ratio Test:converges
Popular Examples
sum from n=1 to infinity of n^{-5/2}sum from k=1 to infinity of sin(1/k)sum from n=1 to infinity of 1/((3n+1)^2)sum from n=1 to infinity of cos((11)/n)sum from n=0 to infinity of 3^n*7^{-n}
Frequently Asked Questions (FAQ)
What is the sum from k=1 to infinity of 2(-1/5)^{2k} ?
The sum from k=1 to infinity of 2(-1/5)^{2k} is converges