Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Limit Comparison Test:diverges

Popular Examples

sum from n=1 to infinity of (-7/9)^{n-1}sum from n=1 to infinity of 1/(5+n^2)sum from n=2 to infinity of 3/(nln(n))sum from n=1 to infinity of 2/((4n^2-1))sum from n=1 to infinity of (e)^{-n}

Frequently Asked Questions (FAQ)

  • What is the sum from n=0 to infinity of (-2)/(n+1) ?

    The sum from n=0 to infinity of (-2)/(n+1) is diverges