Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Comparison Test:converges

Popular Examples

sum from n=0 to infinity of (5n!)/(2^n)sum from n=0 to infinity of 5/(6^n)sum from n=2 to infinity of (3/8)^{4n}sum from n=0 to infinity of 4/((1-4n)^2)sum from n=1 to infinity of n^5e^{n^3}

Frequently Asked Questions (FAQ)

  • What is the sum from n=5 to infinity of 3/(n^2+5n+4) ?

    The sum from n=5 to infinity of 3/(n^2+5n+4) is converges