Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Cauchy's Convergence Condition:diverges

Popular Examples

sum from n=1 to infinity of (2n)/(7n-4)sum from n=2 to infinity of 5/(n^2-n)sum from n=1 to infinity of (n^2)/(n^4)sum from n=5 to infinity of 3/(n^2+5n+4)sum from n=0 to infinity of (5n!)/(2^n)

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of 2/(3n) ?

    The sum from n=1 to infinity of 2/(3n) is diverges