Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Ratio Test:converges

Popular Examples

sum from n=1 to infinity of (ln(1))/nsum from n=0 to infinity}(\sqrt{n of)/nsum from k=2 to infinity of (-0.8)^ksum from n=1 to infinity of (-2+1)^nsum from n=2 to infinity of (n^e)/(n^pi)

Frequently Asked Questions (FAQ)

  • What is the sum from n=2 to infinity of 7e^{-3n} ?

    The sum from n=2 to infinity of 7e^{-3n} is converges