Solution
Solution
Solution steps
Apply the constant multiplication rule:
Apply Series Ratio Test:converges
Popular Examples
sum from k=0 to infinity of (1/3)^ksum from n=0 to infinity of 2/(3-n)sum from n=1 to infinity of-3(8/7)^{n-1}sum from n=0 to infinity of (1+(-1)^n)/nsum from n=0 to infinity of 8^{1/n}
Frequently Asked Questions (FAQ)
What is the sum from n=1 to infinity of (5n^3)/(6^n) ?
The sum from n=1 to infinity of (5n^3)/(6^n) is converges