What is the derivative of x^2-4x+5 ?

The derivative of x^2-4x+5 is 2x-4

What is the first derivative of x^2-4x+5 ?

The first derivative of x^2-4x+5 is 2x-4

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\frac{d}{d x} (x^{2} - 4 x + 5)

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 2 x - 4 + 0

Simplify

= 2 x - 4

\frac{d}{d x} (\frac{π}{4})

\int \frac{1}{x - 10} d x

\int \frac{2}{2 x - 1} d x

d er i v a t i v e - \frac{14}{s ^{6}}

\int 0.5 sin (2 x) d x

What is the derivative of x^2-4x+5 ?
The derivative of x^2-4x+5 is 2x-4
What is the first derivative of x^2-4x+5 ?
The first derivative of x^2-4x+5 is 2x-4