Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Ratio Test:converges

Popular Examples

sum from n=2 to infinity of 4/(5^n)sum from n=0 to infinity of 5/(1+9n^2)sum from n=0 to infinity of ln(4n+1)sum from n=1 to infinity of n*e^{-n}sum from n=0 to infinity of 5/(n+1)

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of 7(0.5)^{n-1} ?

    The sum from n=1 to infinity of 7(0.5)^{n-1} is converges