Solution
Solution
Solution steps
Apply the constant multiplication rule:
Apply Cauchy's Convergence Condition:diverges
Popular Examples
sum from n=3 to infinity of 1/(n^2ln(n))sum from n=1 to infinity of 4/(sqrt(n))sum from n=2 to infinity of (-0.6)^nsum from n=1 to infinity of cos((14)/n)sum from n=1 to infinity of n/((n+1)2^n)
Frequently Asked Questions (FAQ)
What is the sum from k=1 to infinity of 3/k ?
The sum from k=1 to infinity of 3/k is diverges