What is the sum from n=0 to infinity of (1/12)^n ?

The sum from n=0 to infinity of (1/12)^n is 12/11

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sum from n=0 to infinity of (1/12)^n

n = 0 \sum \infty (\frac{1}{12})^{n}

\frac{12}{11}

Decimal

1.09090 \dots

Solution steps

n = 0 \sum \infty (\frac{1}{12})^{n}

Apply Series Geometric Test:

\frac{12}{11}

= \frac{12}{11}

What is the sum from n=0 to infinity of (1/12)^n ?
The sum from n=0 to infinity of (1/12)^n is 12/11