Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Comparison Test:converges

Popular Examples

sum from n=0 to infinity of n/(n^2-2n+1)sum from n=1 to infinity of (4/5)^{n+1}sum from n=0 to infinity of 1/((1-n)^3)sum from n=1 to infinity of 1/(n4^n)sum from n=1 to infinity of 8/(n(n+3))

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of 5/(n^2+49) ?

    The sum from n=1 to infinity of 5/(n^2+49) is converges