What is the limit as x approaches 0+of (1-2x)^{9/x} ?

The limit as x approaches 0+of (1-2x)^{9/x} is 1/(e^{18)}

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limit as x approaches 0+of (1-2x)^{9/x}

x \to 0 + lim ((1 - 2 x)^{\frac{9}{x}})

\frac{1}{e ^{18}}

Decimal

1.523 E - 8

Solution steps

x \to 0 + lim ((1 - 2 x)^{\frac{9}{x}})

Apply exponent rules

= x \to 0 + lim (e^{\frac{9}{x} l n (1 - 2 x)})

Apply the Limit Chain Rule:

\frac{1}{e ^{18}}

= \frac{1}{e ^{18}}

What is the limit as x approaches 0+of (1-2x)^{9/x} ?
The limit as x approaches 0+of (1-2x)^{9/x} is 1/(e^{18)}