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tangent f(x)=-1/((x-5)^2),\at x=-4

解答

切线

f (x) = - \frac{1}{( x - 5 ) ^{2}}, at x = - 4

解答

y = - \frac{2}{729} x - \frac{17}{729}

求解步骤

找到切点:

(- 4, - \frac{1}{81})

计算

f (x) = - \frac{1}{( x - 5 ) ^{2}}

的斜率:

\frac{df ( x )}{d x} = \frac{2}{( x - 5 ) ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2}{729}

找到斜率 m=

- \frac{2}{729}

且穿过

(- 4, - \frac{1}{81})

的直线:

y = - \frac{2}{729} x - \frac{17}{729}

y = - \frac{2}{729} x - \frac{17}{729}

作图

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