What is the limit as z approaches 0 of 1/(sin(z)) ?

The limit as z approaches 0 of 1/(sin(z)) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

limit as z approaches 0 of 1/(sin(z))

z \to 0 lim (\frac{1}{sin ( z )})

diverges

Solution steps

z \to 0 lim (\frac{1}{sin ( z )})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

z \to 0 + lim (\frac{1}{sin ( z )}) = \infty

z \to 0 - lim (\frac{1}{sin ( z )}) = - \infty

= diverges

What is the limit as z approaches 0 of 1/(sin(z)) ?
The limit as z approaches 0 of 1/(sin(z)) is diverges