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Popular Calculus >

integral from 0 to 2 of 3x^2-2x+1

Solution

\int_{0}^{2} 3 x^{2} - 2 x + 1 d x

Solution

6

Solution steps

\int_{0}^{2} 3 x^{2} - 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 3 x^{2} d x - \int_{0}^{2} 2 x d x + \int_{0}^{2} 1 d x

\int_{0}^{2} 3 x^{2} d x = 8

\int_{0}^{2} 2 x d x = 4

\int_{0}^{2} 1 d x = 2

= 8 - 4 + 2

Simplify

= 6

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of 3x^2-2x+1 ?
The integral from 0 to 2 of 3x^2-2x+1 is 6