What is the integral from-1 to 1 of \sqrt[3]{x+1} ?

The integral from-1 to 1 of \sqrt[3]{x+1} is 3/(2^{2/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from-1 to 1 of \sqrt[3]{x+1}

\frac{3}{2 ^{\frac{2}{3}}}

Decimal

1.88988 \dots

Solution steps

Apply u-substitution

Apply the Power Rule

= [\frac{3}{4} u^{\frac{4}{3}}]_{0}^{2}

Compute the boundaries:

\frac{3}{2 ^{\frac{2}{3}}}

= \frac{3}{2 ^{\frac{2}{3}}}

What is the integral from-1 to 1 of \sqrt[3]{x+1} ?
The integral from-1 to 1 of \sqrt[3]{x+1} is 3/(2^{2/3)}