What is the integral from 0 to infinity of e^{-1/5} ?

The integral from 0 to infinity of e^{-1/5} is diverges

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integral from 0 to infinity of e^{-1/5}

\int_{0}^{\infty} e^{- \frac{1}{5}}

diverges

Solution steps

\int_{0}^{\infty} e^{- \frac{1}{5}} d x

Compute the indefinite integral:

\int e^{- \frac{1}{5}} d x = \frac{1}{e ^{\frac{1}{5}}} x + C

Compute the boundaries:

\int_{0}^{\infty} e^{- \frac{1}{5}} d x =

diverges

= diverges

What is the integral from 0 to infinity of e^{-1/5} ?
The integral from 0 to infinity of e^{-1/5} is diverges