What is the integral from 0 to 2 of e^{-x}cos(x) ?

The integral from 0 to 2 of e^{-x}cos(x) is (sin(2)-cos(2))/(2e^2)+1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 2 of e^{-x}cos(x)

\int_{0}^{2} e^{- x} cos (x) d x

\frac{sin ( 2 ) - cos ( 2 )}{2 e ^{2}} + \frac{1}{2}

Decimal

0.58968 \dots

Solution steps

\int_{0}^{2} e^{- x} cos (x) d x

Compute the indefinite integral:

\int e^{- x} cos (x) d x = \frac{e ^{- x} sin ( x )}{2} - \frac{e ^{- x} cos ( x )}{2} + C

Compute the boundaries:

\int_{0}^{2} e^{- x} cos (x) d x = \frac{sin ( 2 ) - cos ( 2 )}{2 e ^{2}} - (- \frac{1}{2})

= \frac{sin ( 2 ) - cos ( 2 )}{2 e ^{2}} - (- \frac{1}{2})

Simplify

= \frac{sin ( 2 ) - cos ( 2 )}{2 e ^{2}} + \frac{1}{2}

What is the integral from 0 to 2 of e^{-x}cos(x) ?
The integral from 0 to 2 of e^{-x}cos(x) is (sin(2)-cos(2))/(2e^2)+1/2