integral from-2 to 2 of e^{2x+2}

Lösung

\int_{- 2}^{2} e^{2 x + 2} d x

\frac{e ^{8} - 1}{2 e ^{2}}

Dezimale

201.64672 \dots

Schritte zur Lösung

\int_{- 2}^{2} e^{2 x + 2} d x

Wende U-Substitution an

= \int_{- 2}^{6} e^{u} \frac{1}{2} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{- 2}^{6} e^{u} d u

Nutze das gemeinsame Integral :

\int e^{u} d u = e^{u}

= \frac{1}{2} [e^{u}]_{- 2}^{6}

Berechne die Grenzen:

e^{6} - \frac{1}{e ^{2}}

= \frac{1}{2} (e^{6} - \frac{1}{e ^{2}})

Vereinfache

= \frac{e ^{8} - 1}{2 e ^{2}}

\int_{0}^{5} \frac{1}{x ^{1.6}} d x

\int_{0}^{2} 9 - x^{2} d x

\int_{2}^{4} (x^{2} - 2 x + 3) d x

\int_{y - 2}^{4 - y^{2}} x d x

\int_{0}^{\frac{π}{6}} sin (θ) d θ