What is the integral from 1 to 0 of e^x ?

The integral from 1 to 0 of e^x is -e+1

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integral from 1 to 0 of e^x

\int_{1}^{0} e^{x} d x

- e + 1

Decimal

- 1.71828 \dots

Solution steps

\int_{1}^{0} e^{x} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{1} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= - [e^{x}]_{0}^{1}

Compute the boundaries:

e - 1

= - (e - 1)

Simplify

= - e + 1

What is the integral from 1 to 0 of e^x ?
The integral from 1 to 0 of e^x is -e+1