What is the integral from 0 to pi of 2pi(sin(x)) ?

The integral from 0 to pi of 2pi(sin(x)) is 4pi

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integral from 0 to pi of 2pi(sin(x))

\int_{0}^{π} 2 π (sin (x)) d x

4 π

Decimal

12.56637 \dots

Solution steps

\int_{0}^{π} 2 π sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 π \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 2 π [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= 2 π 2

Simplify

= 4 π

What is the integral from 0 to pi of 2pi(sin(x)) ?
The integral from 0 to pi of 2pi(sin(x)) is 4pi