What is the integral from-1 to 1 of (10x^2+11) ?

The integral from-1 to 1 of (10x^2+11) is 86/3

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integral from-1 to 1 of (10x^2+11)

\int_{- 1}^{1} (10 x^{2} + 11) d x

\frac{86}{3}

Decimal

28.66666 \dots

Solution steps

\int_{- 1}^{1} 10 x^{2} + 11 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 10 x^{2} d x + \int_{- 1}^{1} 11 d x

\int_{- 1}^{1} 10 x^{2} d x = \frac{20}{3}

\int_{- 1}^{1} 11 d x = 22

= \frac{20}{3} + 22

Simplify

\frac{20}{3} + 22 : \frac{86}{3}

= \frac{86}{3}

What is the integral from-1 to 1 of (10x^2+11) ?
The integral from-1 to 1 of (10x^2+11) is 86/3