What is the integral from y to 8-y^2 of 1 ?

The integral from y to 8-y^2 of 1 is 8-y^2-y

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integral from y to 8-y^2 of 1

\int_{y}^{8 - y^{2}} 1 d x

8 - y^{2} - y

Solution steps

\int_{y}^{8 - y^{2}} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{y}^{8 - y^{2}}

Simplify

= [x]_{y}^{8 - y^{2}}

Compute the boundaries:

8 - y^{2} - y

= 8 - y^{2} - y

What is the integral from y to 8-y^2 of 1 ?
The integral from y to 8-y^2 of 1 is 8-y^2-y