What is the integral from 100 to 200 of (100)/(x^2) ?

The integral from 100 to 200 of (100)/(x^2) is 1/2

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integral from 100 to 200 of (100)/(x^2)

\int_{100}^{200} \frac{100}{x ^{2}} d x

\frac{1}{2}

Decimal

0.5

Solution steps

\int_{100}^{200} \frac{100}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 100 \cdot \int_{100}^{200} \frac{1}{x ^{2}} d x

Apply the Power Rule

= 100 [- \frac{1}{x}]_{100}^{200}

Compute the boundaries:

\frac{1}{200}

= 100 \cdot \frac{1}{200}

Simplify

= \frac{1}{2}

What is the integral from 100 to 200 of (100)/(x^2) ?
The integral from 100 to 200 of (100)/(x^2) is 1/2