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Popular Calculus >

integral from 1 to 2 of (-x+2)

Solution

\int_{1}^{2} (- x + 2) d x

Solution

\frac{1}{2}

+1

Decimal

0.5

Solution steps

\int_{1}^{2} - x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{2} x d x + \int_{1}^{2} 2 d x

\int_{1}^{2} x d x = \frac{3}{2}

\int_{1}^{2} 2 d x = 2

= - \frac{3}{2} + 2

Simplify

- \frac{3}{2} + 2 : \frac{1}{2}

= \frac{1}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (-x+2) ?
The integral from 1 to 2 of (-x+2) is 1/2