What is the integral from 1 to 2 of 3/7 x^2x^2 ?

The integral from 1 to 2 of 3/7 x^2x^2 is 93/35

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integral from 1 to 2 of 3/7 x^2x^2

\int_{1}^{2} \frac{3}{7} x^{2} x^{2} d x

\frac{93}{35}

Decimal

2.65714 \dots

Solution steps

\int_{1}^{2} \frac{3}{7} x^{2} x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{7} \cdot \int_{1}^{2} x^{2} x^{2} d x

Simplify

x^{2} x^{2} : x^{4}

= \frac{3}{7} \cdot \int_{1}^{2} x^{4} d x

Apply the Power Rule

= \frac{3}{7} [\frac{x ^{5}}{5}]_{1}^{2}

Compute the boundaries:

\frac{31}{5}

= \frac{3}{7} \cdot \frac{31}{5}

Simplify

= \frac{93}{35}

What is the integral from 1 to 2 of 3/7 x^2x^2 ?
The integral from 1 to 2 of 3/7 x^2x^2 is 93/35