What is the integral from x to pi/2 of (sin(x))/x ?

The integral from x to pi/2 of (sin(x))/x is \Si(pi/2)-\Si(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from x to pi/2 of (sin(x))/x

\int_{x}^{\frac{π}{2}} \frac{sin ( x )}{x} d x

Si (\frac{π}{2}) - Si (x)

Solution steps

\int_{x}^{\frac{π}{2}} \frac{sin ( x )}{x} d x

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (x)]_{x}^{\frac{π}{2}}

Compute the boundaries:

Si (\frac{π}{2}) - Si (x)

= Si (\frac{π}{2}) - Si (x)

What is the integral from x to pi/2 of (sin(x))/x ?
The integral from x to pi/2 of (sin(x))/x is \Si(pi/2)-\Si(x)