What is the integral from 1 to 8 of 2x^{2/3} ?

The integral from 1 to 8 of 2x^{2/3} is 186/5

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integral from 1 to 8 of 2x^{2/3}

\int_{1}^{8} 2 x^{\frac{2}{3}} d x

\frac{186}{5}

Decimal

37.2

Solution steps

\int_{1}^{8} 2 x^{\frac{2}{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{8} x^{\frac{2}{3}} d x

Apply the Power Rule

= 2 [\frac{3}{5} x^{\frac{5}{3}}]_{1}^{8}

Compute the boundaries:

\frac{93}{5}

= 2 \cdot \frac{93}{5}

Simplify

= \frac{186}{5}

What is the integral from 1 to 8 of 2x^{2/3} ?
The integral from 1 to 8 of 2x^{2/3} is 186/5