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Popular Calculus >

integral from-1 to 3 of 8-4y^2

Solution

\int_{- 1}^{3} 8 - 4 y^{2} d y

Solution

- \frac{16}{3}

+1

Decimal

- 5.33333 \dots

Solution steps

\int_{- 1}^{3} 8 - 4 y^{2} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{3} 8 d y - \int_{- 1}^{3} 4 y^{2} d y

\int_{- 1}^{3} 8 d y = 32

\int_{- 1}^{3} 4 y^{2} d y = \frac{112}{3}

= 32 - \frac{112}{3}

Simplify

32 - \frac{112}{3} : - \frac{16}{3}

= - \frac{16}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 3 of 8-4y^2 ?
The integral from-1 to 3 of 8-4y^2 is -16/3